University Syllabus · B.Com / MBA / Class XII Aligned

Managerial Economics & Project Management

Rigorous, Exam-Ready Master Notes

Demand & Elasticity Production & LVP Advanced Cost Theory CPM & PERT Networks Capital Budgeting NPV June 2024 · May 2025 Solved

Table of Contents

  1. Theory of Demand and Price Elasticity
  2. Production & Short-Run LVP Framework
  3. Advanced Cost Theory & Curves
  4. Market Structures & Profit Calculus
  5. Project Management & Network CPM/PERT
  6. Capital Budgeting & Investment Appraisal
Section 01

Theory of Demand & Price Elasticity of Demand

The Law of Demand The Law of Demand states that, ceteris paribus (all other factors remaining constant), the quantity demanded of a commodity inversely varies with its price. Mathematically, it is expressed as: $$Q_d = f(P) \quad \text{where} \quad \frac{dQ_d}{dP} < 0$$

Movement Along vs. Shift of the Demand Curve

  1. Movement Along the Curve (Change in Quantity Demanded): Caused exclusively by a change in the own price of the commodity. It manifests as:
    • Expansion of Demand: Downward movement to the right as price falls.
    • Contraction of Demand: Upward movement to the left as price rises.
  2. Shift of the Curve (Change in Demand): Caused by shifts in non-price determinants (e.g., consumer income, tastes, price of related goods). It manifests as:
    • Rightward Shift: Increase in demand at all prices.
    • Leftward Shift: Decrease in demand at all prices.

Economic Taxonomy of Goods

Mathematical Formulations of Price Elasticity ($E_p$)

Arc / Percentage Method $$E_p = -\left( \frac{\Delta Q}{\Delta P} \times \frac{P_1}{Q_1} \right)$$
Point Elasticity (Calculus Method) $$E_p = -\left( \frac{dQ}{dP} \times \frac{P}{Q} \right)$$
Geometric Method (Linear Demand Curve) $$E_p = \frac{\text{Lower Segment of the Demand Curve}}{\text{Upper Segment of the Demand Curve}}$$

Point Elasticity Along a Linear Demand Curve

Figure 1 — Point Elasticity Variations

A [Ep = ∞] M [Ep = 1] B [Ep = 0] Elastic Zone (Ep > 1) Inelastic Zone (Ep < 1) Quantity (Q) Price (P) O

Point Elasticity varies continuously from $\infty$ at the vertical axis intercept down to $0$ at the horizontal axis intercept.

Extreme Elasticity Diagrams

Perfect Inelasticity ($E_p = 0$)

Dem (Vertical) O Q P

Perfect Elasticity ($E_p = \infty$)

Dem (Horizontal) O Q P

Market Equilibrium Calculations

Equilibrium Condition Market equilibrium occurs where the quantity demanded equals the quantity supplied: $Q_d = Q_s$.

System 1 (June 2024 Context): Given $D = -10P + 130$ and $S = 15P + 30$.

Setting $D = S$: $$-10P + 130 = 15P + 30 \implies 100 = 25P \implies P^* = 4 \text{ units of currency}$$ Substituting back to find $Q^*$: $$Q^* = -10(4) + 130 = 90 \text{ units}$$

System 2 (May 2025 Context): Given $Q_d = 160 - 6P$ and $Q_s = 100 + 4P$.

Setting $Q_d = Q_s$: $$160 - 6P = 100 + 4P \implies 60 = 10P \implies P^* = 6 \text{ units of currency}$$ Substituting back to find $Q^*$: $$Q^* = 160 - 6(6) = 124 \text{ units}$$

Section 02

Theory of Production & Short-Run Framework

Production maps factor inputs (Land, Labor, Capital, Entrepreneurship) to total physical output. In economics, we divide this study into the short-run and long-run.

Short-Run vs. Long-Run Production Functions

Product Definitions

Mathematical Interpretation of Returns to Scale (RTS)

Let output be $Q = f(L, K)$. If we multiply all inputs by a positive scalar factor $\lambda > 1$:

$$f(\lambda L, \lambda K) = \lambda^k f(L, K) = \lambda^k Q$$
Case Evaluation (June 2024 Question) A firm uses $L_1 = 50$, $K_1 = 5 \implies Q_1 = 1000$ units. Now inputs are exactly doubled: $L_2 = 100$, $K_2 = 10 \implies Q_2 = 2500$ units. Determine the type of returns to scale.

Solution: The inputs increased by a factor of $\lambda = 2$. The output increased by a factor of $\frac{2500}{1000} = 2.5$. Since the output scale factor ($2.5$) is greater than the input scaling factor ($2$), we have: $$\lambda^k > \lambda^1 \implies k > 1$$ Therefore, the firm exhibits Increasing Returns to Scale (IRS).

The Law of Variable Proportions (Three Stages)

Figure 2 — The Three Stages of Production (LVP)

TP AP MP Stage I Stage II Stage III Labor (L) Output O

Rational producers always operate in Stage II, where both AP and MP are declining but remain positive. Stage III features negative marginal returns ($MP < 0$).


Section 03

Advanced Cost Theory & Curves

Cost Classifications

Cost Type Definition & Properties Practical Examples
Explicit Cost Actual out-of-pocket cash payments made to hired/external factors of production. Wages paid to casual labour, raw material costs, electricity, and factory rent.
Implicit Cost The estimated value of inputs supplied by the owner themselves (opportunity costs of self-owned factors). Imputed rent of own factory building, interest on own invested capital.
Opportunity Cost The economic value of the next best alternative foregone when a specific choice is made. Foregone interest earnings on invested funds, foregone salaries of self-employed owners.

Short-Run Curve Geometries

Average Fixed Cost (AFC) is a Rectangular Hyperbola Because TFC remains absolutely constant across all output levels: $$\text{TFC} = \text{Constant} \implies \text{AFC} = \frac{\text{TFC}}{Q} \quad \text{}$$ $$\text{Area} = Q \times \text{AFC} = \text{TFC} = \text{Constant} \quad \text{}$$ This geometric property means the area of the rectangle formed beneath the AFC curve is identical at every single coordinate point.

The Geometric Linkage: Marginal Cost and Average Cost

The mathematical relationship between Average Cost ($AC$ or $ATC$) and Marginal Cost ($MC$) controls the shapes of both curves:

  1. When $\text{MC} < \text{AC}$, the Average Cost curve must fall ($\frac{dAC}{dQ} < 0$).
  2. When $\text{MC} > \text{AC}$, the Average Cost curve must rise ($\frac{dAC}{dQ} > 0$).
  3. When $\text{MC} = \text{AC}$, the Average Cost curve is at its minimum ($\frac{dAC}{dQ} = 0$). This means the MC curve cuts AC (and AVC) exactly at their respective global minimum points.

Section 04

Market Structures & Profit Maximization Calculus

Structural Characteristic Perfect Competition Monopoly
Number of Sellers Infinite (atomistic). Strictly single seller.
Product Nature Homogeneous (identical). Unique product with no close substitutes.
Pricing Role Price Taker (no market control). Price Maker (complete market control).
Demand Curve Shape Infinitely elastic horizontal straight line. Downward sloping demand curve.
Marginal Revenue $\text{Price} = \text{Average Revenue} = \text{Marginal Revenue}$ $\text{Marginal Revenue} < \text{Average Revenue}$

Mathematical Conditions for Profit Maximization ($\Pi$)

First-Order Condition (Necessary) $$\frac{d\Pi}{dq} = 0 \implies \frac{dTR}{dq} - \frac{dTC}{dq} = 0 \implies MR = MC \quad \text{}$$
Second-Order Condition (Sufficient) $$\frac{d^2\Pi}{dq^2} < 0 \implies \frac{d(MR)}{dq} < \frac{d(MC)}{dq}$$ This means the slope of the MC curve must be greater than the slope of the MR curve at the point of intersection (MC must cut MR from below).
Analytical Application (June 2024 Question) A firm's short-run cost function is given as $C = 5q^2 - 50q + 8$, and the market price is Rs. 10 per unit in a perfectly competitive market. Find the profit-maximizing output and total profit.

Step 1: Determine Marginal Revenue (MR)
Since it is perfect competition, price is constant, so: $$TR = P \times q = 10q \implies MR = \frac{d(10q)}{dq} = 10$$ Step 2: Find Marginal Cost (MC)
$$MC = \frac{dC}{dq} = \frac{d(5q^2 - 50q + 8)}{dq} = 10q - 50$$ Step 3: Solve for Equilibrium ($MR = MC$)
$$10 = 10q - 50 \implies 60 = 10q \implies q^* = 6 \text{ units} \quad \text{}$$ Step 4: Verify the Second-Order Condition
$$\frac{d(MC)}{dq} = 10 \quad \text{and} \quad \frac{d(MR)}{dq} = 0 \implies 10 > 0 \quad (\text{Sufficient Condition Met!})$$ Step 5: Calculate Maximum Profit ($\Pi$)
$$\Pi = TR(6) - TC(6)$$ $$TR(6) = 10 \times 6 = 60 \text{ Rs.}$$ $$TC(6) = 5(6)^2 - 50(6) + 8 = 180 - 300 + 8 = -112 \text{ Rs.}$$ $$\Pi = 60 - (-112) = 172 \text{ Rs.} \quad \text{}$$

Section 05

Project Management & Network CPM/PERT Analysis

Project Life Cycle Phases

  1. Initiation: Conceptualization, initial feasibility checks, and goal-setting.
  2. Planning: Designing scheduling networks, budgeting, resource mapping, and scheduling milestones.
  3. Execution: Physical work begins. Design blueprints are converted into real outcomes.
  4. Termination: Delivery, sign-off, close-out audit, and resource releasing.

Methodological Tools: PERT vs. CPM

Network Diagram Construction Case (May 2025 Context)

Using the project configuration below, we map and calculate the Critical Path:

Figure 3 — Project Network Logic Diagram

N1 N2 N3 N4 N5 A: 4w B: 3w C: 5w D: 4w E: 6w (Critical)

Path Analysis: Path 1 ($A \to C \to E$) = $4 + 5 + 6 = 15$ weeks. Path 2 ($B \to D \to E$) = $3 + 4 + 6 = 13$ weeks. The Critical Path is A-C-E (15 Weeks).


Section 06

Capital Budgeting & Investment Appraisal

Working Capital vs. Capital Assets

Working Capital Working Capital refers to the capital of a business which is used in its day-to-day operations. It is computed as Current Assets minus Current Liabilities, incorporating raw materials, cash, and receivables, but explicitly excluding long-term fixed assets like land.

Appraisal Metrics

NPV Equation $$\text{NPV} = \sum_{t=1}^{n} \frac{CF_t}{(1+r)^t} - CF_0 \quad \text{}$$ Acceptance Criteria: Accept a project if $\text{NPV} \ge 0$, and reject if $\text{NPV} < 0$.

Detailed Calculation Case Studies

Case Study 1 (June 2024 Question): Initial cost is Rs. 50,000. Discount rate = 10%. Expected inflows: Year 1 = 15,000; Year 2 = 18,000; Year 3 = 16,000; Year 4 = 12,000. Calculate NPV and evaluate viability.

$$\text{NPV} = \frac{15000}{(1.1)^1} + \frac{18000}{(1.1)^2} + \frac{16000}{(1.1)^3} + \frac{12000}{(1.1)^4} - 50000 \quad \text{}$$ $$\text{PV}_1 = \frac{15000}{1.1} = 13636.36 \text{ Rs.}$$ $$\text{PV}_2 = \frac{18000}{1.21} = 14876.03 \text{ Rs.}$$ $$\text{PV}_3 = \frac{16000}{1.331} = 12021.04 \text{ Rs.}$$ $$\text{PV}_4 = \frac{12000}{1.4641} = 8196.16 \text{ Rs.}$$ $$\text{Total Present Value} = 13636.36 + 14876.03 + 12021.04 + 8196.16 = 48729.59 \text{ Rs.}$$ $$\text{NPV} = 48729.59 - 50000 = -1270.41 \text{ Rs.}$$

Verdict: Reject the project because NPV < 0.

Case Study 2 (May 2025 Question): Initial investment = Rs. 1,00,000. Discount rate = 10%. Expected inflows: Year 1 = 20,000; Year 2 = 30,000; Year 3 = 30,000; Year 4 = 40,000. Calculate NPV and evaluate viability.

$$\text{NPV} = \frac{20000}{(1.1)^1} + \frac{30000}{(1.1)^2} + \frac{30000}{(1.1)^3} + \frac{40000}{(1.1)^4} - 100000 \quad \text{}$$ $$\text{PV}_1 = \frac{20000}{1.1} = 18181.82 \text{ Rs.}$$ $$\text{PV}_2 = \frac{30000}{1.21} = 24793.39 \text{ Rs.}$$ $$\text{PV}_3 = \frac{30000}{1.331} = 22539.44 \text{ Rs.}$$ $$\text{PV}_4 = \frac{40000}{1.4641} = 27320.54 \text{ Rs.}$$ $$\text{Total Present Value} = 18181.82 + 24793.39 + 22539.44 + 27320.54 = 92835.19 \text{ Rs.}$$ $$\text{NPV} = 92835.19 - 100000 = -7164.81 \text{ Rs.}$$

Verdict: Reject the project because NPV < 0.

Critical Review

Most Important Exam Points

Core principles matching past-year questions:

Curve Geometries

  • AFC → Rectangular Hyperbola
  • TFC → Perfectly Horizontal Line
  • MC, AVC, ATC → Classic U-shaped
  • TVC, TC → Inverse S-shaped

Equilibrium Relations

  • MC = MR cuts from below (Profit Max)
  • MC cuts AC & AVC at their minimums
  • At Q=0, TC = TFC (since TVC=0)
  • TC − TVC = TFC (Parallel Curves)

Decision Criteria

  • Accept Project if NPV ≥ 0
  • Reject Project if NPV < 0
  • Critical path tasks have zero float
  • PERT expects probabilistic durations
Past-Paper & Model Questions

Solved High-Yield Practice Questions

Theoretical — 5 Marks

Q: Can short-run Average Fixed Cost (AFC) ever be zero? Explain.

Ans: No. AFC = TFC / Q. In the short run, Total Fixed Cost (TFC) is constant and strictly positive ($\text{TFC} > 0$). As $Q$ grows extremely large, AFC approaches zero asymptotically, but can never equal zero because the numerator is always positive. Thus, the curve is a rectangular hyperbola that never intersects either axis.

Calculus & Profit — 8 Marks

Q: Given market price $P = 20$ and cost function $C = 2q^2 - 10q + 15$, find profit-maximizing output and maximum profit.

Ans: Under perfect competition, $MR = P = 20$. Find MC: $MC = \frac{dC}{dq} = 4q - 10$. Set $MR = MC \implies 20 = 4q - 10 \implies 4q = 30 \implies q^* = 7.5$ units. Verify SOC: $\frac{d(MC)}{dq} = 4 > \frac{d(MR)}{dq} = 0$ (Sufficient condition met). Calculate Profit: $\Pi = TR - TC = (20 \times 7.5) - [2(7.5)^2 - 10(7.5) + 15] = 150 - [112.5 - 75 + 15] = 150 - 52.5 = 97.5$ Rs.

Numerical Network — 8 Marks

Q: An infrastructure asset has tasks: A (6w, pred: none), B (4w, pred: none), C (8w, pred: A), D (5w, pred: B), E (7w, pred: C, D). Find critical path and completion time.

Ans: Build the paths: Path 1: $A \to C \to E \implies 6 + 8 + 7 = 21$ weeks. Path 2: $B \to D \to E \implies 4 + 5 + 7 = 16$ weeks. The Critical Path is A-C-E with a duration of 21 weeks. Total Float for Path 2 is $21 - 16 = 5$ weeks.

Diagrammatic — 5 Marks

Q: Explain why the Average Cost (AC) curve can fall even when Marginal Cost (MC) is rising.

Ans: As long as the absolute value of Marginal Cost remains below Average Cost ($\text{MC} < \text{AC}$), the incremental cost of producing one more unit pulls down the average. Even when MC starts climbing after hitting its minimum, AC continues falling until MC rises enough to intersect it at its exact lowest point.

Revision Sheets

Ultra-Condensed Revision Panels

Demand & Elasticity

  • Law of Demand: $Q_d = f(P)$, $\frac{dQ}{dP} < 0$.
  • Midpoint Elasticity: $E_p = 1$.
  • Substitutes: Cross Elasticity > 0.
  • Complements: Cross Elasticity < 0.

LVP (Short Run)

  • Stage I: MP > AP, ends at Max AP.
  • Stage II: MP decreases to 0 (Rational Zone).
  • Stage III: MP < 0, TP falls.
  • U-shape curves stem from LVP.

Cost Curves

  • $\text{Economic Cost} = \text{Explicit} + \text{Implicit}$.
  • AFC = Rectangular Hyperbola.
  • TC and TVC are parallel.
  • MC cuts AC and AVC at minimums.

NPV & Capital

  • $\text{NPV} = \sum \frac{CF_t}{(1+r)^t} - CF_0$.
  • Accept if NPV ≥ 0.
  • Payback: ignores time value.
  • Working Capital excludes land.

Comprehensive Revision & Exam-Ready Blueprint · Aligned with June 2024 and May 2025 Past Papers